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Question

When an electron jumps from a radius n = to n = 2 of hydrogen atom then it radiates energy of the wavelength ___nm. If required, use hc = 1242 eV.nm.

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Solution

The energy of n = 2 state is
E2=13.6eV4=3.4eV.
The energy of n = state is zero. The wavelength emitted in the given transition is
λ = hcΔE
= 1242eV.nm3.4eV=365nm.


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