When an electron jumps from a radius n = ∞ to n = 2 of hydrogen atom then it radiates energy of the wavelength ___nm. If required, use hc = 1242 eV.nm.
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Solution
The energy of n = 2 state is E2=−13.6eV4=−3.4eV. The energy of n = ∞ state is zero. The wavelength emitted in the given transition is λ = hcΔE = 1242eV.nm3.4eV=365nm.