Question

When an electron jumps from $n_{1}th$ orbit to $n_{2}th$ orbit, the energy radiated is given by

• A. $hv=E_1/E_2$
• B. $hv=E_2/E_1$
• C. $hv=E_1-E_2$
• D. $hv=E_2-E_1$

Answer 1

Answer: (C)

$hv=E_1-E_2$

According to Bohr's model of an atom, the energy radiated due to the transition of electron from higher energy orbit to lower energy orbit is equal to the difference of these energy levels.

$E_1=-13.6\frac{Z^2}{n_1^2}$ and $E_2=-13.6\frac{Z^2}{n_2^2}$

As $n_2<n_1$ $⟹E_1>E_2$

Hence, energy radiated $h\nu =E_1-E_2$