wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

When an equimolar mixture of Cu2S and CuS is titrated with Ba(MnO4)2 in acidic medium, the final product contains Cu2+, SO2 and Mn2+. If the molecular weight of Cu2S, CuS and Ba(MnO4)2 are M1, M2 and M3 respectively then:

A
eq. wt. of Cu2S is M18
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
eq. wt. of CuS is M26
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
eq. wt. of Ba(MnO4)2 is M35
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cu2S and CuS both have same no. of equivalents in mixture
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A eq. wt. of Cu2S is M18
B eq. wt. of CuS is M26
+1Cu22SCu+2++4SO2
So, n-factor of Cu2S = 8
Hence, eq. wt. of Cu2S is M18

+2Cu2SCu+2++4SO2
So, n-factor = 6
Hence, eq. wt. of CuS is M26

Ba(+7MnO4)2Mn+2
So, n-factor = 10
eq. wt. of Ba(MnO4)2 is M310

Clearly, as number of moles of CuS and Cu2S is same but n-factor is different. So, equivalents will be different.

flag
Suggest Corrections
thumbs-up
11
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon