CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equivalent Mass

When an equim...

Question

When an equimolar mixture of $C u_{2} S$ and $C u S$ is titrated with $B a (M n O_{4})_{2}$ in acidic medium, the final product contains $C u^{2 +}$ , $S O_{2}$ and $M n^{2 +}$ . If the molecular weight of $C u_{2} S$ , $C u S$ and $B a (M n O_{4})_{2}$ are $M_{1}$ , $M_{2}$ and $M_{3}$ respectively then:

A

eq. wt. of

C u_{2} S

is

\frac{M_{1}}{8}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

eq. wt. of

C u S

is

\frac{M_{2}}{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

eq. wt. of

B a (M n O_{4})_{2}

is

\frac{M_{3}}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

C u_{2} S

and

C u S

both have same no. of equivalents in mixture

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A eq. wt. of $C u_{2} S$ is $\frac{M_{1}}{8}$
B eq. wt. of $C u S$ is $\frac{M_{2}}{6}$
$+ 1 C u_{2} - 2 S \to C u^{+ 2} + + 4 S O_{2}$
So, n-factor of $C u_{2} S$ = 8
Hence, eq. wt. of $C u_{2} S$ is $\frac{M_{1}}{8}$

$+ 2 C u - 2 S \to C u^{+ 2} + + 4 S O_{2}$
So, n-factor = 6
Hence, eq. wt. of $C u S$ is $\frac{M_{2}}{6}$

$B a (+ 7 M n O_{4})_{2} \to M n^{+ 2}$
So, n-factor = 10
eq. wt. of $B a (M n O_{4})_{2}$ is $\frac{M_{3}}{10}$

Clearly, as number of moles of $C u S a n d C u_{2} S$ is same but n-factor is different. So, equivalents will be different.

Suggest Corrections

thumbs-up

8

Similar questions

Q. When an equimolar mixture of

C u_{2} S

C u S

is titrated with

B a (M n O_{4})_{2}

in acidic medium, the final product contains

C u^{2 +}, S O_{2}

M n^{2 +}

. If the molecular weight of

C u_{2} S, C u S

B a (M n O_{4})_{2}

M_{1}, M_{2}

M_{3}

respectively then,

Q. The mixture of

C u S

(molar weight =

M_{1}

C u_{2} S

(molecular weight =

M_{2}

) is oxidised by

K M n O_{4}

(molecular weight =

M_{4}

) in acidic medium, the product obtained are

C u^{2 +}

S O_{2 +}

. The equivalent weights of

C u S, C u_{2} S

K M n O_{4}

respectively, are :

10

C u_{2} S

C u S

was treated with

200

0.75 M M n O_{4}^{-}

in acid solution producing

S O_{2}

C u^{2 +}

M n^{2 +}

S O_{2}

was boiled off and the excess of

M n O_{4}^{-}

was titrated with

175

1 M F e^{2 +}

solution. Calculate the percentage of

C u S

in the original mixture (to nearest integer).

C u_{2} S

M_{2} S

are isomorphous in which percentage of sulphur is

20.14

12.94

% respectively. The atomic weight of M is:

[Atomic wt. of Cu = 63.5]

Q. The reaction

C u^{2 +} (e q) + 2 C l^{⊖} (a q) \to C u (s) + C l_{2} (g)

E_{c e l l}^{⊖} = - 1.03 V

. This reaction:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Reactions in Solutions

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Equivalent Mass

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon