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Electrical Properties of Colloids

When an exces...

Question

When an excess of a very dilute aqueous solution of KI is added to a very dilute aqueous solution of silver nitrate, the colloidal particles of silver iodide are associated with which of the following Helmholtz double layer?

AgI ¦ Ag⁺¦ I^-

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AgI ¦ K⁺¦ NO₃^-

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AgI ¦ NO₃^- ¦ K⁺

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AgI ¦ I^- ¦ K⁺

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Solution

The correct option is D AgI ¦ I^- ¦ K⁺
As excess of KI has been added, $I^{-}$ ions are adsorbed on AgI forming a layer ( and giving it a negative charge). It then attracts the counter ion $K^{+}$ from the medium forming the second layer (diffused layer).

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Similar questions

When an excess of a very dilute aqueous solution of KI is added to a very dilute aqueous solution of silver nitrate, the colloidal particles of silver iodide are associated with which of the following Helmholtz double layer?

Q. When dilute aqueous solution of

A g N O_{3}

(excess) is added to

K I

solution, positively charged sol particles of

A g I

are formed due to adsorption of ion :

Q. When dilute aqueous solution of

A g N O_{3}

(excess) is added to

K I

solution, positively charge sol of

A g I

in formed due to adsorption of:

Q. The van't Hoff factor for a very dilute aqueous solution of

K [A g {(C N)}_{2}]

is:

Q. The equivalent conductance of silver nitrate solution at

250 K

for an infinite dilution was found to be

133.3 Ω^{- 1} {c m}^{2} {e q u i v}^{- 1}

. The transport number of

{A g}^{+}

ions in very dilute solution of

A g N O_{3}

0.464

. Equivalent conductances of

{A g}^{+}

and

N O_{3}^{-}

(in

Ω^{- 1} {c m}^{2} {e q u i v}^{- 1}

) at infinite dilution are respectively :

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When an excess of a very dilute aqueous solution of KI is added to a very dilute aqueous solution of silver nitrate, the colloidal particles of silver iodide are associated with which of the following Helmholtz double layer?

The correct option is D AgI ¦ I- ¦ K+As excess of KI has been added, I− ions are adsorbed on AgI forming a layer ( and giving it a negative charge). It then attracts the counter ion K+ from the medium forming the second layer (diffused layer).

The correct option is D AgI ¦ I^- ¦ K⁺
As excess of KI has been added, $I^{-}$ ions are adsorbed on AgI forming a layer ( and giving it a negative charge). It then attracts the counter ion $K^{+}$ from the medium forming the second layer (diffused layer).