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Question

When an excess of CO2 is passed through lime water then what will be the sequence of the product?


A

Ca(HCO3)2,CaO

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B

CaO,Ca(HCO3)2

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C

CaCO3,Ca(HCO3)2

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D

Ca(HCO3)2,CaCO3

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Solution

The correct option is C

CaCO3,Ca(HCO3)2


  • When an excess of CO2 (Carbon dioxide) is passed through lime water(Ca(OH)2), the following reaction will takes place:Ca(OH)2(aq)+CO2(g)CaCO3(s)+H2O(l)(Limewater)(Carbondioxide)(Calciumcarbonate)(Water).
  • Again when CO2 is passed through the formed product, we get:CaCO3(s)+H2O(l)+CO2(g)Ca(HCO3)2(aq)(Calciumcarbonate)(Water)(Carbondioxide)(Calciumbicarbonate).
  • Hence, the correct sequence of product formation is CaCO3,Ca(HCO3)2.

Therefore, among the above given options, option (c) is correct.


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