When an experiment is done to find the surface tension of a liquid on earth by capillary rise method, the height of the liquid column is 4 cm.When the same experiment is done on another planet whose mass is 4 times and radius is twice that of the earth, then the height of liquid column is ....... cm.

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Solution

The correct option is A 4
$h = \frac{2 T c o s Θ}{r s g}$
$g = \frac{G M}{R^{2}}$
$g^{1} = \frac{G (4 M)}{(2 R)^{2}} = g$
$∴$ h remains same $= 4 c m$

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The correct option is A 4h=2TcosΘrsgg=GMR2g1=G(4M)(2R)2=g∴ h remains same =4cm

The correct option is A 4
$h = \frac{2 T c o s Θ}{r s g}$
$g = \frac{G M}{R^{2}}$
$g^{1} = \frac{G (4 M)}{(2 R)^{2}} = g$
$∴$ h remains same $= 4 c m$