When an ideal mono atomic gas undergoes an adiabatic expansion, its temperature and volume are related by the equation ${T V}^{n} =$ constant, the value of $n$ will be:

1.33

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0.67

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2.33

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1

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Solution

The correct option is D $0.67$
For a mono-atomic gas
$T V^{r - 1} =$ constant
$\Rightarrow n = r - 1 = 1.67 - 1 = 0.67$

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When an ideal mono atomic gas undergoes an adiabatic expansion, its temperature and volume are related by the equation TVn= constant, the value of n will be:

The correct option is D 0.67For a mono-atomic gasTVr−1=constant⇒n=r−1=1.67−1=0.67

When an ideal mono atomic gas undergoes an adiabatic expansion, its temperature and volume are related by the equation ${T V}^{n} =$ constant, the value of $n$ will be:

The correct option is D $0.67$
For a mono-atomic gas
$T V^{r - 1} =$ constant
$\Rightarrow n = r - 1 = 1.67 - 1 = 0.67$