When an inductor, a capacitor and a resistor are connected in series across a source of alterating emf, thepotential difference across the inductor, capacitor and resistor are 70V, 30V and 30V respectively. Find theemf of the source
A
50V
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B
60V
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C
30V
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D
80V
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Solution
The correct option is A50V V=√V2R+[VL−Vc]2 =√302+[70−30]2 =√302+402=√502
=50 V