When an iron cylinder of diameter 0.20cm and length 30cm is kept parallel to a magnetic field of intensity 4800A/m the cylinder acquires a pole strength of 9Am. Find the permeability of the material of the rod?
A
0.075222×10−4H/m
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B
9.522×10−4H/m
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C
75.22×10−4H/m
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D
7.522×10−4H/m
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Solution
The correct option is D7.522×10−4H/m Pole Strength = m=9A*m B = Therefore,