When an object of height 1 cm is kept at a distance of 4 cm from a concave mirror, its upright image of height 1.5 cm is formed at a distance of 6 cm behind the mirror. Calculate the focal length of the mirror ___

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Solution

u = - 4 cm

v = 6 cm

Mirror formula $\frac{1}{f}$ = $\frac{1}{v}$ + $\frac{1}{u}$

$\frac{1}{f}$ = $\frac{1}{- 4}$ + $\frac{1}{6}$

f = -12 cm

Focal length of the mirror is 12 cm.

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When an object of height 1 cm is kept at a distance of 4 cm from a concave mirror, its upright image of height 1.5 cm is formed at a distance of 6 cm behind the mirror. Calculate the focal length of the mirror ___

u = - 4 cm v = 6 cm Mirror formula 1f = 1v + 1u 1f = 1−4 + 16 f = -12 cm Focal length of the mirror is 12 cm.

u = - 4 cm

v = 6 cm

Mirror formula $\frac{1}{f}$ = $\frac{1}{v}$ + $\frac{1}{u}$

$\frac{1}{f}$ = $\frac{1}{- 4}$ + $\frac{1}{6}$

f = -12 cm

Focal length of the mirror is 12 cm.