When an optically active amine $A$ having molecular formula $C_{4} H_{11} N$ is subjected to Hofmann's exhaustive methylation followed by hydrolysis, an alkene $B$ is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine $A$ is:

C H_{3} C H C H_{2} | N H_{2} C H_{3}

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C H_{3} N H - C H | C H_{3} - C H_{3}

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C H_{3} N H C H_{2} | C H_{3} C H_{3}

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C H_{3} C H_{2} C H_{2} C H_{2} N H_{2}

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Solution

The correct option is A $C H_{3} C H C H_{2} | N H_{2} C H_{3}$
The only optically active molecule is as shown.

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When an optically active amine A having molecular formula C4H11N is subjected to Hofmann's exhaustive methylation followed by hydrolysis, an alkene B is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine A is:

The correct option is A CH3CHCH2|NH2CH3The only optically active molecule is as shown.

When an optically active amine $A$ having molecular formula $C_{4} H_{11} N$ is subjected to Hofmann's exhaustive methylation followed by hydrolysis, an alkene $B$ is produced which upon ozonolysis and subsequent hydrolysis yields formaldehyde and propanal. The amine $A$ is:

The correct option is A $C H_{3} C H C H_{2} | N H_{2} C H_{3}$
The only optically active molecule is as shown.