When aqueous solution of cupric bromide is electrolyzed the product obtained at cathode will be

C u

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H_{2}

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B 4_{2}

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O_{2}

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Solution

The correct option is B $C u$
The discharge potential of $C u^{2 +}$ ion is lower than the discharge potential of $H_{3} O^{+}$ .
Hence, during electrolysis of aqueous cupric bromide solution, copper is deposited at cathode.

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