Question

When aromatic hydrocarbons are treated with chloroform and aluminum chloride, the following reaction sequence is observed. $ArH\underset{AlC{l}_3}{\overset{CHC{l}_3}{\to }}A\underset{AlC{l}_3}{\overset{ArH}{\to }}B\underset{AlC{l}_3}{\overset{ArH}{\to }}F$
$B\stackrel{AlC{l}_3}{\to }C\stackrel{A{r}_{3}CH}{\to }D+E$
What is the structure of compound C?

• A. $A{r}_2{C}^{+}HAlC{l}_4^{-}$
• B. $A{r}_{2}CH$
• C. $Ar{C}^{+}{H}_{2}AlC{l}_4^{-}$
• D. $ArC{H}_2$

Answer 1

The correct option is A $A{r}_2{C}^{+}HAlC{l}_4^{-}$

The structure of compound C is $A{r}_2{C}^{+}HAlC{l}_4^{-}$.
$ArH\underset{AlC{l}_3}{\overset{CHC{l}_3}{\to }}\underset{A}{ArCHC{l}_2}\underset{AlC{l}_3}{\overset{ArH}{\to }}\underset{B}{A{r}_{2}CHCl}\underset{AlC{l}_3}{\overset{ArH}{\to }}\underset{F}{A{r}_{3}CH}$
$\underset{B}{A{r}_{2}CHCl}\stackrel{AlC{l}_3}{\to }\underset{C}{A{r}_2{C}^{+}HAlC{l}_4^{-}}\stackrel{A{r}_{3}CH}{\to }\underset{D}{A{r}_{2}C{H}_2}+\underset{E}{A{r}_3{C}^{+}Al{C}_4^{-}}$