Question

When bauxite is heated with $NaOH$ solution, the water soluble compound formed is ___________.

• A. $NaAl{O}_2$
• B. $N{a}_{3}Al{O}_3$
• C. $Al(OH{)}_3$
• D. $A{l}_2{O}_3$

Answer 1

The correct option is A $NaAl{O}_2$

When bauxite is heated with $NaOH$ solution, the aluminum oxide present in bauxite reacts with $NaOH$ to form water soluble sodium meta aluminate $\left(NaAl{O}_2\right)$.

The reaction is as follows:
$A{l}_2{O}_3.2H_{2}O\left(s\right)+2NaOH\left(aq\right)\to 2NaAl{O}_2\left(aq\right)+3H_{2}O\left(l\right)$

Option A is correct.