When $B C l_{3}$ reacts with excess of $H_{2} O$ in the presence of $N a O H$ . Then the formed product(s) is/are.

N a [B (O H)_{4}]

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N a C l

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H O C l

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H C l

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Solution

The correct options are
A $N a [B (O H)_{4}]$
D $N a C l$
When $B C l_{3}$ reacts with excess of $H_{2} O$ in the presence of $N a O H$ . Then the formed products are $N a [B (O H)_{4}]$ and $N a C l$ .
$2 B C l_{3} + 3 H_{2} O + 2 N a O H \to N a [B (O H)_{4}] + N a C l$
Hence option A &B are correct

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When $B C l_{3}$ reacts with excess of $H_{2} O$ in the presence of $N a O H$ . Then the formed product(s) is/are.