When benzene sulphonic acid and p-nitrophenol are treated with $N a H C O_{3},$ the gases released, respectively, are:

S O_{2}, N O_{2}

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S O_{2}, N O

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S O_{2}, C O_{2}

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C O_{2}, C O_{2}

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Solution

The correct option is D $C O_{2}, C O_{2}$
$P h S O_{3} H + N a H C O_{3} \to P h S O_{3} N a + H_{2} O + C O_{2}$
(I)
$p - N O_{2} - C_{6} H_{4} - O H + N a H C O_{3} \to p - N O_{2} - C_{6} H_{4} O N a + H_{2} O + C O_{2}$
(II)

Since both (I) and (II) are stronger acids than $H_{2} C O_{3},$ they are capable of evolving $C O_{2}$ with $N a H C O_{3} .$
$H C O_{3}^{⊖} + H^{\oplus} \to H_{2} O + C O_{2} ↑$

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