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Standard XII

Chemistry

Introduction to Aromatic Compounds

When boron ox...

Question

When boron oxide is reduced with carbon in an electric furnace, a disproportionation reaction takes place.

$2 B_{2} O_{3} + 7 C ⟶ A + B$

It is found that Compound $A$ is harder than diamond. What is the physical state of compound $B$ ?

Solid

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Liquid

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Gas

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None of these

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Solution

The correct option is C Gas
$2 B_{2} O_{3} + 7 C ⟶ B_{4} C + 6 C O$
$↓$ $↓$
$(A)$ $(B)$

Since compound $A$ is harder than Diamond, it should be $B_{4} C$ . It is because $B_{4} C$ is very hard.

Compound $(B)$ is $C O$ .

So the physical state of compound $(B)$ is gas.

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Similar questions

Q. When boron oxide is reduced with carbon in an electric furnace, a disproportionation reaction takes place.

2 B_{2} O_{3} + 7 C ⟶ A + B

It is found that Compound

A

is harder than diamond.

Which of the following statements is incorrect about compound

A

Q. When

F e C r_{2} O_{4}

(chromite) is reduced with Carbon in an electric-arc furnace:

Q. Assertion :Decomposition of hydrogen peroxide is an example of disproportionation reaction. Reason: In a disproportionation reaction, an element in one oxidation state is simultaneously oxidised and reduced.

(a) Acids dissolve in water and produce positively charged ions. Draw the structure of these positive ions.

(b) Explain why Carbon tetrachloride does not dissolve in water.

(c) Elements Q and S react together to form an ionic compound. Under normal conditions, which physical state will the compound QS exist in ?

(d) Can Q and S, both be metals ? Justify your answer.

(e) The property which is characteristic of an electrovalent compound is that :

A. it is easily vaporized,

B. it has a high melting point,

C. it is a weak electrolyte,

D. it often exists as a liquid.

(f) When a metal atom becomes an ion :

A. it loses electrons and is oxidized,

B. it gains electrons and is reduced,

C. it gains electrons and is oxidized,

D. it loses electrons and is reduced.

Q. When

M n O_{2}

is fused with

K O H

in the presence of

K N O_{3}

as an oxidizing agent, it gives a dark green compound (A).
Compound (A) disproportionates in acidic solution to give purple compound (B).
An alkaline solution of compound (B) oxidises

K I

to compound (C) whereas an acidified solution of compound (B) oxidises

K I

to (D). Identify (A), (B), (C), and (D).

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When boron oxide is reduced with carbon in an electric furnace, a disproportionation reaction takes place.2B2O3+7C⟶A+BIt is found that Compound A is harder than diamond. What is the physical state of compound B?

The correct option is C Gas2B2O3+7C⟶B4C+6CO ↓ ↓ (A) (B)Since compound A is harder than Diamond, it should be B4C. It is because B4C is very hard.Compound (B) is CO. So the physical state of compound (B) is gas.

When boron oxide is reduced with carbon in an electric furnace, a disproportionation reaction takes place.

$2 B_{2} O_{3} + 7 C ⟶ A + B$

It is found that Compound $A$ is harder than diamond. What is the physical state of compound $B$ ?

The correct option is C Gas
$2 B_{2} O_{3} + 7 C ⟶ B_{4} C + 6 C O$
$↓$ $↓$
$(A)$ $(B)$

Since compound $A$ is harder than Diamond, it should be $B_{4} C$ . It is because $B_{4} C$ is very hard.

Compound $(B)$ is $C O$ .

So the physical state of compound $(B)$ is gas.