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Oxides and Oxoanions

When Br2 is...

Question

When ${B r}_{2}$ is passed into hot aqueous solution of ${N a}_{2} {C O}_{3}$ :

{B r}^{-}

is formed by reduction

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B r O_{3}^{-}

is formed by oxidation

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C O_{2}

is evolved

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all of the above are correct

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Solution

The correct option is D all of the above are correct
First carbonate reacts with water and forms unstable acid which on dissociation gives $C O_{2}$ .
${N a}_{2} {C O}_{3} + H_{2} O ⟶ 2 N a O H + H_{2} {C O}_{3}$
$H_{2} {C O}_{3} ⟶ H_{2} O + C O_{2}$
The formed $N a O H$ reacts with bromine and auto redox happens.
$6 N a O H + {B r}_{2} \to 5 N a B r b y r e d u c t i o n + N a B r O_{3} b y o x i d a t i o n + 3 H_{2} O$
0 -1 +5

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Similar questions

{C O}_{2}

{N a}_{2} {C O}_{3}

B r_{2}

B r {O_{3}}^{-}

B r_{2}

N a O H

B r^{-}

B r {O_{3}}^{-}

H_{2} S

C r^{3 +}, C d^{2 +}, H g^{2 +} a n d C o^{2 +},

C O_{2}

B r_{2}

B r^{-}

{B r O_{3}}^{-}

3 B r_{2} + 6 O H^{-} \to 5 B r^{-} + {B r O_{3}}^{-} + 3 H_{2} O

B r_{2}

= M

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