When brakes are applied to a bus when its speed is 5 m/s, the retardation produced is $25 c m s^{- 2}$ and the bus takes 20 s to stop. Calculate the distance travelled by the bus during this time.

50 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2000 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 50 m
$v = u + a t$
$0 = u - 0.25 \times 20$
$u = 5 m / s$

$s = u t + \frac{1}{2} a t^{2}$
$s = 5 \times 20 + \frac{1}{2} \times (- 0.25) \times (20^{2})$
$s = 50 m$

Suggest Corrections

Similar questions

Q. When brakes are applied to a bus, the retardation produced is

25 c m s^{- 2}

and the bus takes

20 s

to stop. Find the distance travelled by the bus during this time.

When brakes are applied to a bus, the retardation produced is 25 $c m s^{- 2}$ and the bus takes 20 s to stop.Calculate:(i) the initial velocity of bus,and (ii) the distance travelled by bus during this time.

Q. When brakes are applied to a bus, the retardation produced is

25 c m s^{- 2}

and the bus takes 20 s to stop. Calculate the initial velocity of the bus.

Q. The brakes applied to a bike produce retardation of

5 {m/s}^{2}

. If the bike takes

4 s

to stop after the application of brakes, calculate the distance it travels during this time.

Q. When a bus driver travelling at a speed of 20m/s applied brakes and brings the bus to rest in 10 seconds, then retardation will be

Join BYJU'S Learning Program

When brakes are applied to a bus when its speed is 5 m/s, the retardation produced is 25cm s−2 and the bus takes 20 s to stop. Calculate the distance travelled by the bus during this time.

The correct option is B 50 mv=u+at0=u−0.25×20u=5 m/ss=ut+12at2s=5×20+12×(−0.25)×(202)s=50 m

When brakes are applied to a bus when its speed is 5 m/s, the retardation produced is $25 c m s^{- 2}$ and the bus takes 20 s to stop. Calculate the distance travelled by the bus during this time.

The correct option is B 50 m
$v = u + a t$
$0 = u - 0.25 \times 20$
$u = 5 m / s$

$s = u t + \frac{1}{2} a t^{2}$
$s = 5 \times 20 + \frac{1}{2} \times (- 0.25) \times (20^{2})$
$s = 50 m$