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Assigning Oxidation Numbers

When BrO3- ...

Question

When $B r O_{3}^{-}$ ion reacts with $B r^{-}$ ion in acidic medium, $B r_{2}$ is liberated. The ratio of molecular weight and equivalent weight of $K B r O_{3}$ is:

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Solution

Change in oxidation state of Br in $B r O_{3}^{-}$ $= 5 - 0 = 5$ .
So, ratio of molecular weight and equivalent weight of $K B r O_{3}$ $= \frac{M}{M / 5} = 5$ .

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B r O_{3}^{-}

ion reacts with

B r^{-}

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B r_{2}

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K B r O_{3}

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{B r}_{2}

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{B r}_{2}

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