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Electric Power

When bulb 1 i...

Question

When bulb 1 is screwed in, but bulb 2 is unscrewed, the power generated in bulb 1 is

A

4 watts

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B

12 watts

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C

36 watts

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D

48 watts

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Solution

The correct option is D 48 watts
In this case, only lower loop active.
Thus, power dissipation in bulb 1 is $P_{1} = V^{2} / R_{1} = (12)^{2} / 3 = 48 W$

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