When $C_{2} H_{5} O H$ is heated with acidified $K_{2} C r_{2} O_{7}$ it forms $C H_{3} C O O H$ .
It is an example of:

Molecular rearrangement

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Hydrolysis

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Oxidation

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Dehydration

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Solution

The correct option is C Oxidation
In Organic reactions instead of change in oxidation state rather removal of hydrogen or addiiton of oxygen to a carbon atom is considered oxidation and so is above.

As Potassium Dichromate is a powerful oxidising agent, the alcohol will be oxidised, first to the aldehyde (acetaldehyde in this case) and then to the carboxylic acid (acetic acid), The orange dichromate ion in turn is reduced to a green $C r^{3 +}$ salt in solution.

Reaction

$C_{2} H_{5} O H a c i d i f i e d K_{2} C r_{2} O_{7} - ---------- \to C H_{3} C H O ⟶ C H_{3} C O O H$

Option C is correct.

Suggest Corrections

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