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Zinc Ion

When calomel ...

Question

When calomel reacts with ${N H}_{4} O H$ we get:

H g ({N H}_{2}) C l + H g

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({N H}_{2}) {H g}_{2} C l

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{H g}_{2} O

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H g O

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Solution

The correct option is A $H g ({N H}_{2}) C l + H g$
Calomel is ${H g}_{2} {C l}_{2}$ .

It reacts with ammonium hydroxide to form $({H g N H}_{2} C l + H g)$ .

It is black in colour.

$H g_{2} C l_{2} + 2 N H_{4} O H \to H_{2} N - H g - C l + H g ↓ b l a c k + N H_{4} C l + 2 H_{2} O$

Option A is correct.

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