When CH 2- CH - COOH is reduced with LiAlH 4- the compound formed isA- CH 3 CH 2 CH 2 OHB- CH 3 CH 2 CHOC- CH 3 CH 2 COOHD- CH 2- CH - CH 2 OH

The correct option is D CH2 = CH CH2OHLiAlH4 cannot reduce double bond ...

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When CH 2= CH...

Question

When CH₂ = CH - COOH is reduced with LiAlH₄ , the compound formed is

CH₃CH₂CH₂OH

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CH₃CH₂CHO

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CH₃CH₂COOH

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CH₂ = CH - CH₂OH

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When CH₂ = CH - COOH is reduced with LiAlH₄ , the compound formed is

$W h e n C H_{2} = C H - C O O H i s r e d u c e d b y L i A I H_{4}, t h e c o m p o u n d o b t a i n e d i s :$

C H_{2} = C H - C H_{2} O H \to C H_{2} = C H - C H O

C H_{3} - C O O H \to C H_{3} C O N H_{2}

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

C H_{3} - C H_{2} - C H | C O O H - C H_{2} - C l | C H - C H_{2} - C H_{3}

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