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Bond Order and Enthalpy

When chlorine...

Question

When chlorine gas and hydrogen gas react to form hydrogen chloride, what will be the change of enthalpy of the reaction? (bond energies are at the end of this test)

A

+ 245 k J / m o l

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B

+ 185 k J / m o l

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C

- 185 k J / m o l

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D

- 1105 k J / m o l

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E

+ 1105 k J / m o l

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Solution

The correct option is C $- 185 k J / m o l$
$H_{2} + C l_{2} \to 2 H C l$
$Δ H = Σ bond energy of reactants - Σ bond energy of products$
$Δ H = E_{H - H} + E_{C l - C l} - 2 E_{H - C l}$
$Δ H = 437 + 244 - 2 (433)$
$Δ H = - 185 k J / m o l$

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