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Byju's Answer

Standard XII

Chemistry

Stoichiometry

When chlorine...

Question

When chlorine reacts with a gas X, an explosive inorganic compound Y is formed. Then X and Y will be :

X = O_{2}

and

Y = N C l_{3}

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X = N H_{3}

and

Y = N C l_{3}

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X = O_{2}

and

Y = N H_{4} C l

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X = N H_{3}

and

Y = N H_{4} C l

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Solution

The correct option is B $X = N H_{3}$ and $Y = N C l_{3}$
When $N H_{3}$ reacts with excess of $C l$ an explosive substance $N C l_{3}$ is formed.
$N H_{3} + 3 C l_{2} \to N C l_{3} + 3 H C l$
X is $N H_{3}$ and Y is $N C l_{3}$ .

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Similar questions

Q. When excess of

C l_{2}

reacts with ammonia, the products formed are:

C O_{2} + N H_{3} + H_{2} O \to X

X + N a C l \to Y + N H_{4} C l

'Y' in the above reaction is:

In a given reaction, barium hydroxide reacts with ammonium chloride to form product X and Y. Identify X and Y.
$B a (O H)_{2} + N H_{4} C l \to X + Y$

Q. A compound of boron X reacts at

200^{\circ} C

temperature with

N H_{3}

to give another compound

Y

which is called as inorganic benzene. The compound

Y

is a colourless liquid and is highly sensitive. Its melting point is

- 57^{\circ} C

. The compound

X

with excess

N H_{3}

and at a still higher temperature gives boron nitride

{(B N)}_{n}

. The compounds

X

and

Y

respectively are:

A compound of B (Boron), X reacts at $200^{\circ} C$ with $N H_{3}$ to give another compound Y which is called as inorganic benzene. The compound Y is colorless liquid and is highly light sensitive. The compound X with excess of $N H_{3}$ and at still higher temp gives $(B N)_{n}$ . The compound X and Y respectively.

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When chlorine reacts with a gas X, an explosive inorganic compound Y is formed. Then X and Y will be :

The correct option is B X=NH3 and Y=NCl3When NH3 reacts with excess of Cl an explosive substance NCl3 is formed.NH3+3Cl2→NCl3+3HClX is NH3 and Y is NCl3.

The correct option is B $X = N H_{3}$ and $Y = N C l_{3}$
When $N H_{3}$ reacts with excess of $C l$ an explosive substance $N C l_{3}$ is formed.
$N H_{3} + 3 C l_{2} \to N C l_{3} + 3 H C l$
X is $N H_{3}$ and Y is $N C l_{3}$ .