Question

When ${Cl}_2$ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from:

• A. Zero to $-1$ and zero to $+3$
• B. Zero to $+1$ and zero to $-3$
• C. Zero to $+1$ and zero to $-5$
• D. Zero to $-1$ and zero to $+5$

Answer 1

The correct option is D Zero to $-1$ and zero to $+5$

The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is

$3C{l}_2+6NaOH⟶NaCl{O}_3+5NaCl+3H_{2}O$

Oxidation number of $Cl$ is $0$ in $C{l}_2$, $-1$ in $NaCl$ and $+5$ in $NaCl{O}_3$

So the oxidation number of chlorine changes from Zero to -1 and Zero to +5.

Hence, the correct option is $D$