When $C l_{2}$ is passed through moist slaked lime, the compound formed is :

C a O_{2} C l_{2}

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C a O_{2} C l

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C a O C l_{2}

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C a C l_{2} O_{4}

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Solution

The correct option is B $C a O C l_{2}$
When $C l_{2}$ is passed through moist slaked lime, the compound formed is $C a O C l_{2}$ . The reaction is as follows:
$C a (O H)_{2} + C l_{2} \to C a O C l_{2} + H_{2} O$

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