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Potassium Permanganate

When CO2 ga...

Question

When $C O_{2}$ gas is passed into ${M n O}_{4}^{2 -}$ solution, a disproportionation reaction takes place.
$3 M n O_{4}^{2 -} + 4 H^{+} \to M n O_{2} + 2 M n O_{4}^{-} + H_{2} O$
If true enter 1, else enter 0.

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Solution

Aqueous $C O_{2}$ releases $H^{+}$ which can convert $M n O_{4}^{2 -}$ into $M n O_{2}$ and $M n O_{4}^{-}$ .
It is a disproportionation reaction as $M n O_{4}^{2 -}$ $(M n = + 6)$ is oxidised into $M n O_{4}^{-} (M n = + 7)$ as well as reduced into $M n O_{2} (M n = + 4)$ .

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Similar questions

3 M n O_{4}^{2 -} + 4 H^{+} ⟶ M n O_{2} + 2 M n O_{4}^{-} + 2 H_{2} O

2 C u^{+}

\to

C u^{2 +}

C u^{0}

3 M n O_{4}^{2 -}

4 H^{+}

\to

2 M n O_{4}^{-}

M n O_{2}

2 H_{2} O

2 K M n O_{4}

△ - \to

K_{2} M n O_{4}

M n O_{2}

O_{2}

2 M n O_{4}^{-}

3 M n^{2 +}

2 H_{2} O

⟶

5 M n O_{2}

4 H^{+}

(a) 2 C u^{+} \to C u^{2 +} + C u (b) 3 M n O_{4}^{2 -} + 4 H^{+} \to 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O (c) 2 K M n O_{4} \to K_{2} M n O_{4} + M n O_{2} + O_{2} (d) 2 M n O_{4}^{-} + 3 M n^{2 +} + 2 H_{2} O \to 5 M n O_{2} + 4 H^{+}

2 C u^{+}

\to

C u^{2 +}

C u^{0}

3 M n O_{4}^{2 -}

4 H^{+}

\to

2 M n O_{4}^{-}

M n O_{2}

2 H_{2} O

2 K M n O_{4}

△ - \to

K_{2} M n O_{4}

M n O_{2}

O_{2}

2 M n O_{4}^{-}

3 M n^{2 +}

2 H_{2} O

⟶

5 M n O_{2}

4 H^{+}

3 H N O_{2} ⟶ 2 N O + H N O_{3} + H_{2} O

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