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Reaction of Acids with Metal Carbonate

When CO2 is...

Question

When $C O_{2}$ is passed through the suspension of $M g C O_{3}, M g (O H)_{2}$ (basic carbonate), the product formed is:

M g C O_{3}

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M g O

and

H_{2} O

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M g (H C O_{3})_{2}

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M g C O_{3}

and

C O_{2}

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Solution

The correct option is C $M g (H C O_{3})_{2}$
$M g C O_{3} + M g (O H)_{2} + C O_{2} \to M g (H C O_{3})_{2}$

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