When conc. $H_{2} S O_{4}$ is treated with $K_{4} [F e (C N)_{6}]$ , $C O$ gas is evolved. By mistake, somebody used diluted $H_{2} S O_{4}$ instead of conc. $H_{2} S O_{4}$ , then the gas evolved is :

C O

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H C N

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N_{2}

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C O_{2}

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Solution

The correct option is A $H C N$
The reactions are as follows:
$K_{4} F e (C N)_{6} + 6 H_{2} S O_{4} + 6 H_{2} O \to 2 K_{2} S O_{4} + F e S O_{4} + 3 (N H_{4})_{2} S O_{4} + 6 C O$ .

$3 K_{4} [F e (C N)_{6}] + 6 H_{2} S O_{4} \to 12 H C N + F e_{2} [F e (C N)_{6}] + 6 K_{2} S O_{4}$

The gas evolved is $H C N$ .

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