When concentrated $H_{2} S O_{4}$ is added to dry $K N O_{3}$ , brown fumes evolves. These fumes are

S O_{2}

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S O_{3}

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N O

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N O_{2}

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Solution

The correct option is D $N O_{2}$
When nitrate salts are treated with concentrated $H_{2} S O_{4}$ , it gives brown fumes of $N O_{2}$
$2 K N O_{3} + H_{2} S O_{4} \to 2 K H S O_{4} + H N O_{3}$
$4 H N O_{3} \to 4 N O_{2} B r o w n f u m e s + O_{2} + 2 H_{2} O$

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