When concentrated HCl is added to a solution of $[C o (H_{2} O)_{6}]^{2 +}$ ion, an intense blue colour develops due to the formation which one of the following?

[C o C l_{6}]^{4 -}

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[C o C l_{4}]^{2 -}

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[C o C l_{2} (H_{2} O)_{4}]

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[C o C l (H_{2} O)_{5}]^{+}

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Solution

The correct option is A $[C o C l_{6}]^{4 -}$
When concentrated HCl is added to a solution of $[C o (H_{2} O)_{6}]^{2 +}$ ion, an intense blue colour develops due to the formation of $[C o C l_{6}]^{4 -}$ . $C l^{-}$ replaces all $H_{2} O$ molecules.

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(b) $[C o (H_{2} O)_{6}]^{2 +}$ is transformed into $[C o C l_{4}]^{2 -}$
(c) tetrahedral complexes have smaller crystal field splitting than octahedral complexes
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When concentrated HCl is added to a solution of [Co(H2O)6]2+ ion, an intense blue colour develops due to the formation which one of the following?

The correct option is A [CoCl6]4−When concentrated HCl is added to a solution of [Co(H2O)6]2+ ion, an intense blue colour develops due to the formation of [CoCl6]4−. Cl− replaces all H2O molecules.

When concentrated HCl is added to a solution of $[C o (H_{2} O)_{6}]^{2 +}$ ion, an intense blue colour develops due to the formation which one of the following?

The correct option is A $[C o C l_{6}]^{4 -}$
When concentrated HCl is added to a solution of $[C o (H_{2} O)_{6}]^{2 +}$ ion, an intense blue colour develops due to the formation of $[C o C l_{6}]^{4 -}$ . $C l^{-}$ replaces all $H_{2} O$ molecules.