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Sulphuric Acid

When copper r...

Question

When copper reacts with conc. $H_{2} S O_{4}$ , the oxidation state of sulphur is not changed.
If true enter 1, else enter 0.

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Solution

$C u + 2 H_{2} {S O}_{4} \to {S O}_{2} + 2 H_{2} O + {S O}_{4}^{2 -} + {C u}^{2 +}$

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