When copper turnings are added to silver nitrate solution, a blue coloured solution is formed after some time. It is because copper:

displaces silver from the solution

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forms a blue coloured complex with

A g N O_{3}

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is oxidised to

C u^{2 +}

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is reduced to

C u^{2 +}

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Solution

The correct options are
B displaces silver from the solution
C is oxidised to $C u^{2 +}$
The colour is due to $C u (N O_{3})_{2}$ where the oxidation state of $C u$ is $+ 2$ . Loss of electron is oxidation.
Hence option A and C is correct.

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