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Ampere's Circuital Law

When current ...

Question

When current changes from $4 A$ to $0 A$ in $0.1 s$ in an inductor the induced emf is found to be $100 V$ , then find the value of self-inductance is :

A

0.5 H

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B

2 H

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C

2.5 H

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D

1 H

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Solution

The correct option is C $2.5 H$
$Δ I = (4 - 0) = 4 A$
$t = 0.1 s$
$e = 100 V$
$L = \frac{- e}{\frac{d I}{d t}} = \frac{- 100}{\frac{4}{0.1}} = - \frac{10}{4} = 2.5 H$

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