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Question

When current is coil changes from 5 A to 2 A in 0.1 s, an average of 50 V is produced. The self-inductance of the coil is.

A
6 H
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B
0.67 H
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C
1.67 H
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D
3 H
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Solution

The correct option is C 1.67 H
Inudctor opposes change in curren, as the current is decreased, the inductor will convert magnetic energy into electrical by creating a potential difference. The voltage drop across inductor is given by
V=Ldidt
50=L25.1 here negative sign is because voltage is increasing instead of drop across inductor
50=L25.1
L=1.67H.

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