When CuSO 4 -5 H 2 O is heated- then the products are-A- CuSO 4- 3 H 2 O and CO 2B- CuSO 4- 10 H 2 O and 5 H 2 OC- CuSO 4 and 5 H 2 OD- None of the above

The correct option is C CuSO_4 and 5 H_2OCuSO_4.5H_2O → CuSO_4 + 5 H_2O The above compound loses its water of crystallization ...

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When $C u S O_{4} .5 H_{2} O$ is heated, then the products are:

C u S O_{4} . 3 H_{2} O a n d C O_{2}

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C u S O_{4} .10 H_{2} O a n d 5 H_{2} O

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C u S O_{4} a n d 5 H_{2} O

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None of the above

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{CuSO}_{4} .5 H_{2} O

When $C u S O_{4} .5 H_{2} O$ is heated the products are:

When $C u S O_{4} .5 H_{2} O$ is heated, the products are:

C u S O_{4} .5 H_{2} O

C u S O_{4} .5 H_{2} O

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