Question

When $CuS{O}_4$ is electrolysed using platinum electrodes:

• A. Copper is liberated at cathode, sulphur at anode
• B. Copper is liberated at cathode, oxygen at anode
• C. Sulphur is liberated at cathode, oxygen at anode
• D. Oxygen is liberated at cathode, copper at anode

Answer 1

The correct option is B Copper is liberated at cathode, oxygen at anode

$CuS{O}_4\rightleftharpoons C{u}^{2+}+S{O}_4^{2-}$
$H_{2}O\rightleftharpoons H^{+}+O{H}^{-}$
At Cathode: $C{u}^{2+}+2e^{-}\to Cu$
At anode: $4O{H}^{-}\to 2H_{2}O+O_2+4e^{-}$