Question

When denominator is rationalised, then the number $\frac{3+\sqrt{2}}{4\sqrt{2}}$ becomes?

• A. $\frac{2-3\sqrt{2}}{8}$
• B. $\frac{2+3\sqrt{2}}{4}$
• C. $\frac{2-3\sqrt{2}}{4}$
• D. $\frac{2+3\sqrt{2}}{8}$

Answer 1

The correct option is D $\frac{2+3\sqrt{2}}{8}$

Rationalising the denominator means converting it into a rational number from an Irrational number

Hence, for this number $\frac{3+\sqrt{2}}{4\sqrt{2}}$, multiply and divide it by $\sqrt{2}$

Thus, the new number becomes $\frac{3\sqrt{2}+2}{8}.$