Question

When dilute sodium chloride is electrolysed using graphite electrodes, the cation which is discharged at the cathode most readily. $[N{a}^{1+},O{H}^{1-},H^{1+},C{l}^{1-}]$

Answer 1

Correct answer :$H^{1-}$

At cathode:
Both $N{a}^{+}and{H}^{+}$are present near the cathode. but the discharge potential of $H^{+}$is lower than that of $N{a}^{+}$ion.so,$H^{+}$ ions are discharged in preference to $N{a}^{+}$ions.
$H^{+}+e^{-}\to H$
$H+H\to H_2$