When dilute sulphuric acid is added to granulated zinc placed in a test-tube, the observation made is :
(1) the surface of the metal turns shiny
(2) the reaction mixture turns milky
(3) odour of sulphur dioxide is observed
(4) a colourless and odourless gas evolves with bubbles

Open in App

Solution

When zinc reacted with dilute hydrochloric acid, it gives zinc chloride and hydrogen gas is evolved, hydrogen gas is colourless and odourless gas which evolves with bubbles.
$Zn (s) + 2 HCl (aq) \to {ZnCl}_{2} (aq) + H_{2} (g)$

Hence, the correct answer is option 4.

Suggest Corrections

Similar questions

Q. When dilute hydro-chloric acid is added to granulated zinc placed in a test tube, the observation made is
(1) the surface of the metal turns shining
(2) the reaction mixture turns milky
(3) odour of chlorine is observed
(4) a colourless and odorless gas evolves with bubbles

Q. When zinc metal reacts with dilute sulphuric acid, a gas is evolved. Which one is a correct statement about the nature of this gas ?
(1) colourless with suffocating odour
(2) reddish brown and odourless
(3) colourless and sweet smelling
(4) colourless and odourless

Q. When dilute hydrochloric acid is added to granulated zinc placed in a test tube, the observation made is:

When a student added Zinc granules to dilute $H C l$ , a colourless and odourless gas was evolved, which was tested with a burning match stick, it was observed that:

Q. Acetic acid is heated with

N a_{2} C O_{3}

in a test tube. A colourless and odourless gas (X) is evolved. The gas turns lime water milky. Identify X.

Join BYJU'S Learning Program

When dilute sulphuric acid is added to granulated zinc placed in a test-tube, the observation made is : (1) the surface of the metal turns shiny (2) the reaction mixture turns milky (3) odour of sulphur dioxide is observed (4) a colourless and odourless gas evolves with bubbles

When zinc reacted with dilute hydrochloric acid, it gives zinc chloride and hydrogen gas is evolved, hydrogen gas is colourless and odourless gas which evolves with bubbles. Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) Hence, the correct answer is option 4.

When dilute sulphuric acid is added to granulated zinc placed in a test-tube, the observation made is :
(1) the surface of the metal turns shiny
(2) the reaction mixture turns milky
(3) odour of sulphur dioxide is observed
(4) a colourless and odourless gas evolves with bubbles

When zinc reacted with dilute hydrochloric acid, it gives zinc chloride and hydrogen gas is evolved, hydrogen gas is colourless and odourless gas which evolves with bubbles.
$Zn (s) + 2 HCl (aq) \to {ZnCl}_{2} (aq) + H_{2} (g)$

Hence, the correct answer is option 4.