When dilute sulphuric acid is taken in a beaker and zinc metal is stirred into, _______ gas is bubbled off to obtain salt.

H_{2} S

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H_{2}

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H_{2} O

(g)

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O_{2}

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Solution

The correct option is D $H_{2}$
When dilute sulphuric acid is taken in a beaker and zinc metal is stirred into, hydrogen gas is bubbled off to obtain salt, i.e., zinc sulphate. Zinc metal displaces hydrogen ion in $H_{2} S O_{4}$ which is bubbled off.

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Similar questions

Q. When

S O_{2}

gas is bubbled into

H_{2} S

gas:

Suppose, in your lab, you have run out of dilute Sulphuric acid. You require dilute $H_{2} S O_{4}$ for an important synthesis but only have concentrated Sulphuric acid, water and a glass beaker. How will you synthesize dilute $H_{2} S O_{4}$ ?

Q. When zinc reacts with dilute sulphuric acid, a salt is formed with the release of a gas. The gas produced during this puts off a burning candle with a pop sound. The gas evolved during this reaction is:

Q. Assertion :

H_{2} S

reacts with oxygen under standard conditions in acid medium to give

H_{2} O

and sulphur. Reason:

E_{H^{+} / O_{2} / P t}^{o} > E_{H^{+} / H_{2} S / S}^{o}

Q. When zinc reacts with dilute sulphuric acid, hydrogen gas is released.

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When dilute sulphuric acid is taken in a beaker and zinc metal is stirred into, _______ gas is bubbled off to obtain salt.

The correct option is D H2When dilute sulphuric acid is taken in a beaker and zinc metal is stirred into, hydrogen gas is bubbled off to obtain salt, i.e., zinc sulphate. Zinc metal displaces hydrogen ion in H2SO4 which is bubbled off.

The correct option is D $H_{2}$
When dilute sulphuric acid is taken in a beaker and zinc metal is stirred into, hydrogen gas is bubbled off to obtain salt, i.e., zinc sulphate. Zinc metal displaces hydrogen ion in $H_{2} S O_{4}$ which is bubbled off.