When x3+3x2−kx+4 is divided by (x−2), the remainder is 2k then the value of k is
A
6
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B
−6
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C
2
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D
−2
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Solution
The correct option is D6 When x3+3x2−kx+4 is divided by (x−2), the remainder is 2k ∴(x3+3x2−kx+4)−2k is exactly divisible by (x−2) ⇒x=2 will satisfy the expression [x3+3x2−kx+4−2k] ⇒(2)3+3(2)2−k(2)+4−2k=0 ⇒8+12−2k+4−2k=0 ⇒24−4k=0 ⇒k=244=6