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Question

When x3+3x2kx+4 is divided by (x2), the remainder is 2k then the value of k is

A
6
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B
6
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C
2
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D
2
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Solution

The correct option is D 6
When x3+3x2kx+4 is divided by (x2), the remainder is 2k
(x3+3x2kx+4)2k is exactly divisible by (x2)
x=2 will satisfy the expression [x3+3x2kx+42k]
(2)3+3(2)2k(2)+42k=0
8+122k+42k=0
244k=0
k= 244=6

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