When equal quantities of an oil, water and mercury are poured into a beaker, the order in which the liquids arrange themselves from bottom to top is

mercury, water, oil.

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water, mercury, oil.

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water, oil, mercury.

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mercury, oil, water.

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Solution

The correct option is A mercury, water, oil.
$\begin{matrix} The one with high density will be at bottom and low density at top order of density of < water ∠ mercury so mercury will be at bottom, water in middle and oil at top. \end{matrix}$

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When equal quantities of an oil, water and mercury are poured into a beaker, the order in which the liquids arrange themselves from bottom to top is

The correct option is A mercury, water, oil. The one with high density will be at bottom and low density at top order of density of < water ∠ mercury so mercury will be at bottom, water in middle and oil at top.

The correct option is A mercury, water, oil.
$\begin{matrix} The one with high density will be at bottom and low density at top order of density of < water ∠ mercury so mercury will be at bottom, water in middle and oil at top. \end{matrix}$