When equal volumes of the following solutions are mixed- the precipitation of AgCl K sp -1-8 - 10-10 will occur with-A- 10-4 M Ag -and 10-4 M Cl -B- 10-5 M Ag -and 10-5 M Cl -C- 10-5 M Ag -and 10-6 M Cl -D- 10-10 M Ag -and 10-10 M Cl -

The correct option is A 10^ 4 M (Ag^+) and 10^ 4 M (Cl^ )Precipitation will occur when Q gt; K_sp. Q = 10^ 4× 10^ 4 = 10^ 8 gt; K_sp(1.8 × 10^ 10) ...

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Byju's Answer

Standard XII

Physics

Order of Magnitude

When equal vo...

Question

When equal volumes of the following solutions are mixed, the precipitation of $A g C l (K_{s p} = 1.8 \times 10^{- 10})$ will occur with:

10^{- 4} M (A g^{+}) and 10^{- 4} M (C l^{-})

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10^{- 5} M (A g^{+}) and 10^{- 5} M (C l^{-})

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10^{- 5} M (A g^{+}) and 10^{- 6} M (C l^{-})

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10^{- 10} M (A g^{+}) and 10^{- 10} M (C l^{-})

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Solution

The correct option is A $10^{- 4} M (A g^{+}) and 10^{- 4} M (C l^{-})$
Precipitation will occur when $Q > K_{s p}$ .
$Q = 10^{- 4} \times 10^{- 4} = 10^{- 8} > K_{s p} (1.8 \times 10^{- 10})$

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When equal volumes of the following solutions are mixed, the precipitation of AgCl (Ksp=1.8×10−10) will occur with:

The correct option is A 10−4 M (Ag+) and 10−4 M (Cl−)Precipitation will occur when Q>Ksp. Q=10−4×10−4=10−8>Ksp(1.8×10−10)

When equal volumes of the following solutions are mixed, the precipitation of $A g C l (K_{s p} = 1.8 \times 10^{- 10})$ will occur with:

The correct option is A $10^{- 4} M (A g^{+}) and 10^{- 4} M (C l^{-})$
Precipitation will occur when $Q > K_{s p}$ .
$Q = 10^{- 4} \times 10^{- 4} = 10^{- 8} > K_{s p} (1.8 \times 10^{- 10})$