When equal volumes of two substances are mixed, tbe specific gravity of the mixture is 4. When equal weights of the same substances are mixed, the specific gravity of the mixture is 3. The specific gravity of the two substances could be:

6 and 2

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3 and 4

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2.5 and 3.5

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5 and 3

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Solution

The correct option is A 6 and 2
$4 = \frac{V d_{1}}{V d_{2}}$
or $d_{1} + d_{2} = 8$ (i)
$3 = \frac{m + m}{(m / d_{1}) + (m / d_{2})}$
or $\frac{2 d_{1} d_{2}}{d_{1} + d_{2}} = 3$ (ii)
Solving Eqs. (i) and (ii), we get
$d_{1} = 6$ and $d_{2} = 2$

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Q. If

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When equal volumes of two substances are mixed, tbe specific gravity of the mixture is 4. When equal weights of the same substances are mixed, the specific gravity of the mixture is 3. The specific gravity of the two substances could be:

The correct option is A 6 and 24=Vd1Vd2or d1+d2=8 (i)3=m+m(m/d1)+(m/d2)or 2d1d2d1+d2=3 (ii)Solving Eqs. (i) and (ii), we getd1=6 and d2=2

The correct option is A 6 and 2
$4 = \frac{V d_{1}}{V d_{2}}$
or $d_{1} + d_{2} = 8$ (i)
$3 = \frac{m + m}{(m / d_{1}) + (m / d_{2})}$
or $\frac{2 d_{1} d_{2}}{d_{1} + d_{2}} = 3$ (ii)
Solving Eqs. (i) and (ii), we get
$d_{1} = 6$ and $d_{2} = 2$