Question

When ethanoic acid is heated with ${\mathrm{NaHCO}}_3$, the gas evolved is

• A. $H_2$
• B. ${CO}_2$
• C. ${CH}_4$
• D. $CO$

Answer 1

The correct option is B

${\mathrm{CO}}_2$

Explanation:

• When ethanoic acid $\left({\mathrm{CH}}_3\mathrm{COOH}\right)$ is heated with sodium bicarbonate $\left({\mathrm{NaHCO}}_3\right)$, the gas evolved is carbon dioxide $\left({\mathrm{CO}}_2\right)$ along with the formation of sodium acetate $\left({\mathrm{CH}}_3\mathrm{COONa}\right)$ and water $\left({\mathrm{H}}_2\mathrm{O}\right)$.
• The chemical equation is as follows:
• ${\mathrm{CH}}_3\mathrm{COOH}\left(\mathrm{l}\right)+{\mathrm{NaHCO}}_3\left(\mathrm{s}\right)\to {\mathrm{CH}}_3\mathrm{COONa}\left(\mathrm{aq}\right)+{\mathrm{CO}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

Final Answer:

The correct option is (B).