When ethanoic acid is treated with aqueous $N a H C O_{3}, C O_{2}$ is liberated. The carbon atom in this $C O_{2}$ comes from:

methyl group of ethanoic acid

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carboxylic group of ethanoic acid

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methylene group of ethanoic acid

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bicarbonate group of

N a H C O_{3}

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Solution

The correct option is D bicarbonate group of $N a H C O_{3}$
$C H_{3} C O O H + N a H C O_{3} \to C H_{3} C O O N a + H_{2} O + C O_{2}$

$C O_{2}$ comes from bicarbonate because the acidic hydrogen of ethanoic acid reacts with $N a H C O_{3}$ , which decomposes to give $C O_{2}$ .

Option D is correct.

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Similar questions

Q. The functional group in ethanoic acid is ___________.

Name the functional group of the product formed when ethanol reacts with ethanoic acid.

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N a H C O_{3}, C O_{2}

is liberated. The

^{'} C^{'}

C O_{2}

comes from:

State the meaning of functional group in a carbon compound. Write the functional group present in
(i) ethanol and
(ii) ethanoic acid and also draw their structures

When propionic acid is treated with aqueous sodium bicarbonate, $C O_{2}$ is liberated. The C of $C O_{2}$ comes from:

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When ethanoic acid is treated with aqueous NaHCO3,CO2 is liberated. The carbon atom in this CO2 comes from:

The correct option is D bicarbonate group of NaHCO3CH3COOH+NaHCO3→CH3COONa+H2O+CO2CO2 comes from bicarbonate because the acidic hydrogen of ethanoic acid reacts with NaHCO3, which decomposes to give CO2.Option D is correct.

When ethanoic acid is treated with aqueous $N a H C O_{3}, C O_{2}$ is liberated. The carbon atom in this $C O_{2}$ comes from: